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A mixture containing only Na(2) CO(3) an...

A mixture containing only `Na_(2) CO_(3)` and `K_(2) CO_(3)` and weighing `1.22 g` was dissolved in water to form `100 mL` of solution: `20 mL` of this solution required `40 mL` of `0.1 N HCl` for neutralisation.
a. Calculate the weight of `K_(2) CO_(3)` in the mixture.
b. If another `20 mL` of the same solution is treated with excess of `BaCl_(2)`, what will be the weight of precipitate thus obtained? (Molarcular of `Na_(2)CO_(3) = 106`, `K_(2) CO_(3) = 138, BaCO_(3) = 197.4`)

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To solve the problem step by step, we will break it down into parts as per the question requirements. ### Given Data: - Total weight of the mixture (Na₂CO₃ + K₂CO₃) = 1.22 g - Volume of solution = 100 mL - Volume of solution taken for titration = 20 mL - Volume of HCl used = 40 mL - Normality of HCl = 0.1 N ...
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