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4.08 g of a mixture of BaO and an unknow...

`4.08 g` of a mixture of `BaO` and an unknown carbonate `MCO_(3)` was heated strongly. The residue weighed `3.64 g`. This was dissolved in `100 mL` of `1 N HCl`. The excess of acid required of `16 mL` of `2.5 N NaOH` for complete neutralisation. Identify the matal `M`.

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To solve the problem step by step, we will follow the given information and use stoichiometry to identify the metal \( M \) in the carbonate \( MCO_3 \). ### Step 1: Calculate the weight of CO2 lost during heating The initial weight of the mixture is given as \( 4.08 \, g \) and the residue after heating is \( 3.64 \, g \). The weight of the CO2 lost can be calculated as follows: \[ \text{Weight of } CO_2 = \text{Initial weight} - \text{Residue weight} = 4.08 \, g - 3.64 \, g = 0.44 \, g \] ...
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