The three elements A, B and C form three compounds AB, AC and BC. AB contains 75% of A, AC contains 57.14% of C while BC contains 11.11% of B. Prove that these results are in accordance to law of reciprocal proportions.

Explanation

`AB = 75% A, 25% B`
`AC = 42.86% A, 57.14% C`
`BC = 11.11% B, 88.89% C`
In `AB`:
`25 g` of `B` combines with `75 g of A`
`1 g of B` combines with `(75)/(25) = 3 g of A`
In `BC`:
`11.11 g of B` combines with `88.89 g of C`.
`1 g of B` combines with `(88.89)/(11.11) = 8 g of C`.
Ratio of `A` and `C` which combines with a fixed mass of `B` `(1 g) = 3 : 8`
Similarly, the ratio of `A` and `C` in `AC = (42.86)/(42.86).(57.14)/(42.86)`
`= 1 : 1.333`
The two ratios are `A:C`
`(3)/(1) : (8)/(1.333)`
`{:(3 : 6),(1 : 2):}`
Hence, the law of reciprocal proportions is verified.