`0.1653 g` aluminium reacts completely with `0.652 g` chlorine to form chloride of aluminium.
a. What is the empirical formula of the compound?
b. If molecular mass of the compound is 267 amu, calculate the molecular formula of the compound.

Explanation

To solve the problem step by step, we will break it down into two parts: finding the empirical formula and then determining the molecular formula.

### Part a: Finding the Empirical Formula

1. **Calculate the moles of Aluminium (Al)**:
- Given mass of Aluminium = 0.1653 g
- Molar mass of Aluminium = 27 g/mol
- Moles of Al = Mass / Molar mass = 0.1653 g / 27 g/mol = 0.00612 mol (approximately)
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