Home
Class 11
CHEMISTRY
An orgainc compound contains 43.98% C, 2...

An orgainc compound contains `43.98% C`, `2.09% H`, and `37.2% Cl`. Calculate its empirical formula.

Text Solution

AI Generated Solution

To calculate the empirical formula of the organic compound containing 43.98% Carbon (C), 2.09% Hydrogen (H), and 37.2% Chlorine (Cl), we will follow these steps: ### Step 1: Convert percentages to grams Assume we have 100 grams of the compound. This means we have: - 43.98 g of Carbon - 2.09 g of Hydrogen - 37.2 g of Chlorine ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.1 Objective Questions|6 Videos
  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.1 Objective Questions (Single Correct)|3 Videos
  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 Objective|2 Videos
  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

An organic compound contains C = 40%, H = 13.33% , and N = 46.67% . Its empirical formula will be

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

A compound contains 34.8% Oxygen, 52.2% carbon and 13.0% Hydrogen. What is the empirical formula of the compound ?

An organic compound has 68.327% C, 6.406% H, 25.267% CI. Calculate the molecular formula of the compound if its vapour density is 70.25.

An organic compound is found to contain C - 40%. 0 = 53.34% and H = 6.66%. Its empirical formula is

A compound is composed of 2.2% hydrogen, 26.6% carbon and 71.2% oxygen. Calculate the empirical formula of the compound. If its molecular mass is 90, find its molecular formula.

An organic compound containes C=74.0%, H=8.65% and N=17.3% . Its empirical formul ais

A compound contains 10% C, 0.8% H and 89.2% Cl by mass. Determine its simplest formula. (R.A.M.: H = 1, C = 12, CI = 35.5)

If the elemental composition of butyric acid is found to be 54.4% C, 9.13% H, and 36.5% O, determine the empirical formula.

A substance on analysis, gave the following percentage composition : Na = 43.4 %, C = 11.3%, O = 45.3 %. Calculate the empirical formula. (Na = 23, C = 12, O = 16).