Home
Class 11
CHEMISTRY
If 10^(21) molecules are removed from 20...

If `10^(21)` molecules are removed from 200 mg of `CO_(2),` the number of moles of `CO_(2)` left is

Text Solution

Verified by Experts

`:' 6.023 xx 10^(23)` molecules of `CO_(2) = 44 g`
`:. 10^(21)` molecules of `CO_(2) = (44 xx 10^(21))/(6.023 xx 10^(23))`
`= 7.31 xx 10^(-2) = 73.1 mg`
`:. CO_(2)` left `= 200 - 73.1 = 126.9 mg`
Also, moles of `CO_(2) = ("Weight")/("Molecular Weight") = (126.9 xx 10^(-3))/(44)`
`= 2.88 xx 10^(-3)`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.1 Objective Questions|6 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.1 Objective Questions (Single Correct)|3 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

One mole of CO_(2) contains:

When x molecules are removed from 200 mg of N_(2)O . 2.89 xx 10^(-3) moles of N_(2)O are left. x will be

Calculate the number of moles in 22 g of CO_(2)

From 200 mg of CO_(2), 10^(21) molecules are removed. How many grams and moles of CO_(2) are left.

From 200 mg of CO_(2) when x molecules are removed, 2.89 xx 10^(-3) moles of CO_(2) are left. x will be

An aqueous solution contains 980 mg of H_(2)SO_(4) , 3.01xx10^(21) molecules of H_(2)SO_(4) are removed from this solution. How many moles of H_(2)SO_(4) are left in the resultant solution.

Calculate the number of molecules in 33 g of CO_2 .

Calculate the number of molecules in 44 g of CO_2 .

Calculate number of molecules in 1 ml of Co_(2) at NTP.

0.6 g of carbon was burnt in the air to form CO_(2) . The number of molecules of CO_(2) introduced into the will be : C+O_(2)toCO_(2)