`1.878 g` of `MBr_(X)` when heated in a stream of `HCl` gas was comletely converted to chloride `MCl_(X)` which weighted `1.0 g` The specific heat of metal is `0.14 cal g^(-1)`. Calculate the molemular weight of the metal bromide.

Explanation

To find the molecular weight of the metal bromide (MBrₓ), we will follow these steps:

### Step 1: Identify the Reaction
The reaction can be represented as:
\[ \text{MBr}_x + \text{x HCl} \rightarrow \text{MCl}_x + \text{x HBr} \]

### Step 2: Write the Mass Relationships
From the problem, we know:
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