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How much BaCl(2) would be needed to make...

How much `BaCl_(2)` would be needed to make `250 mL` of a solution having same eoncentration of `Cl^(o+)` as the one containing `3.78 g` of `NaCl` per `100 mL`.

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To solve the question, we need to determine how much BaCl₂ is required to create a solution that has the same concentration of Cl⁻ ions as a solution containing 3.78 g of NaCl per 100 mL. Here’s a step-by-step breakdown of the solution: ### Step 1: Calculate the moles of NaCl First, we need to find the number of moles of NaCl in 3.78 g. - Molar mass of NaCl = 22.99 (Na) + 35.45 (Cl) = 58.44 g/mol - Moles of NaCl = mass / molar mass = 3.78 g / 58.44 g/mol ...
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