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Mole fraction of I(2) in C(6) H(6) is 0....

Mole fraction of `I_(2)` in `C_(6) H_(6)` is 0.2. Calculate molality of `I_(2)` in `C_(6) H_(6)`. `(Mw of C_(6) H_(6) = 78 g mol^(-1))`

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To calculate the molality of \( I_2 \) in \( C_6H_6 \) (benzene) given that the mole fraction of \( I_2 \) is 0.2, we can follow these steps: ### Step 1: Understand the Definitions - **Mole Fraction (\( X \))**: The mole fraction of a component in a solution is the ratio of the number of moles of that component to the total number of moles of all components in the solution. - **Molality (m)**: Molality is defined as the number of moles of solute per kilogram of solvent. ### Step 2: Identify the Components - Let \( I_2 \) be the solute (A). ...
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