Calculate molality of 1 litre solution of 95% `H_(2) SO_(4)` by volume. The density of solution is `1.84 g mL^(-1)`.

Explanation

To calculate the molality of a 1-liter solution of 95% H₂SO₄ by volume with a density of 1.84 g/mL, we can follow these steps:

### Step 1: Determine the mass of the solution
Given that the density of the solution is 1.84 g/mL, we can calculate the mass of 1 liter (1000 mL) of the solution.

\[ \text{Mass of solution} = \text{Density} \times \text{Volume} = 1.84 \, \text{g/mL} \times 1000 \, \text{mL} = 1840 \, \text{g} \]
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