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A sample of H(2) SO(4) (density 1.787 g ...

A sample of `H_(2) SO_(4)` (density `1.787 g mL^(-1)`) si labelled as 86% by weight. What is the molarity of acid? What volume of acid has to be used to make `1 L` of `0.2 M H_(2) SO_(4)` ?

Text Solution

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a. `M = (% "by weight" xx 10 xx d)/(Mw_(2)) = (86 xx 10 xx 1.787)/(98) = 15.68`
b. `M_(1) V_(1) = M_(2) V_(2)`
`15.68 xx V_(1) = 0.2 xx 1`
`V_(1) = 0.01274 L = 12.74 mL`
c. `W_(1) =` Weight of `H_(2) O`
= Weight of solution - Weight of solute
`= 100 - 86 = 14 g`
`m = (W_(2) xx 1000)/(Mw_(2) xx W_(1))`
`= (86 xx 1000)/(98 xx 14) = 62.68`
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