Home
Class 11
CHEMISTRY
KCL contains 52 % of potassium, Kl conta...

`KCL` contains 52 % of potassium, `Kl` contains 23.6% of potassium, and `ICI` contains 77.8% of iodine. Show that the above data is in agreement with the law of reciprocal proportions.

Text Solution

AI Generated Solution

The correct Answer is:
To show that the given data is in agreement with the law of reciprocal proportions, we will follow these steps: ### Step 1: Gather the Data We have the following information: - KCl contains 52% potassium (K) and 48% chlorine (Cl). - KI contains 23.6% potassium (K) and 76.4% iodine (I). - ICl contains 77.8% iodine (I) and 22.2% chlorine (Cl). ### Step 2: Calculate the Mass Ratios We will calculate the mass ratios of potassium and iodine that react with a fixed mass of chlorine. 1. **For KCl:** - Mass of Cl = 48 g - Mass of K = 52 g - Ratio of K to Cl = 52 g K / 48 g Cl = 1.08 g K per 1 g Cl 2. **For ICl:** - Mass of I = 77.8 g - Mass of Cl = 22.2 g - Ratio of I to Cl = 77.8 g I / 22.2 g Cl = 3.5 g I per 1 g Cl ### Step 3: Establish the Ratios Now, we can compare the ratios of potassium and iodine that react with the same mass of chlorine. - From KCl: 1.08 g K reacts with 1 g Cl - From ICl: 3.5 g I reacts with 1 g Cl ### Step 4: Calculate the Ratio of Potassium to Iodine To find the ratio of potassium to iodine, we can set up the following relationship based on the previous calculations: - Ratio of K to I = (1.08 g K) / (3.5 g I) ### Step 5: Simplify the Ratio Now we simplify the ratio: 1.08 / 3.5 = 0.30857 To express this in a more understandable form, we can multiply both sides to find a simple ratio: Let’s express it as: - K : I = 1 : (3.5 / 1.08) Calculating this gives us approximately: - K : I = 1 : 3.24 ### Step 6: Compare with KI Now we will also calculate the ratio from KI: - KI contains 23.6% K and 76.4% I. - Ratio of K to I in KI = 23.6 g K / 76.4 g I = 0.30857 ### Conclusion Both ratios derived from KCl and KI are approximately equal, confirming that the data is in agreement with the law of reciprocal proportions. ### Final Result Thus, we conclude that the data supports the law of reciprocal proportions, as the ratios of the masses of potassium and iodine that react with a fixed mass of chlorine are consistent.
To show that the given data is in agreement with the law of reciprocal proportions, we will follow these steps: ### Step 1: Gather the Data We have the following information: - KCl contains 52% potassium (K) and 48% chlorine (Cl). - KI contains 23.6% potassium (K) and 76.4% iodine (I). - ICl contains 77.8% iodine (I) and 22.2% chlorine (Cl). ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Subjective (Limiting Reagent)|2 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Subjective (Empirical And Molecular Formulae)|4 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 Fill In The Blanks|1 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

metal combines with oxygen to form two oxides, having the following composition: (i) 0.398 g of the first metal oxide contains 0.318g of metal. (ii) 0.716 g of the second oxide contains 0.636g of the metal. Show that the above data agrees with the law of multiple proportions.

The three elements A, B and C form three compounds AB, AC and BC. AB contains 75% of A, AC contains 57.14% of C while BC contains 11.11% of B. Prove that these results are in accordance to law of reciprocal proportions.

Sulphur and oxygen are known to form two compounds. The sulphur content in one of these is 51 % while in the other is 41 %. Show that this data is in agreement with the law of multiple proportions.

Sulphur and oxygen are known to form two compounds. The sulphur content in one of these is 51 % while in the other is 41 %. Show that this data is in agreement with the law of multiple proportions.

An element forms two oxides containing 50% and 40% of the element by mass. Prove that the results are in agreement with the law of multiple proportions.

Aluminium oxide contains 52.90% aluminium and carbon dioxide contains 27.27% carbon. Calculate the percentage of aluminium in aluminium carbide assuming that the law of reciprocal proportions is true.

On analysis it was found that the black oxide of copper and red oxide of copper contain 80% and 89% of copper respectively. Show that this data is in accordance with law of multiple proportions.

On analysis it was found that the black oxide of copper and red oxide of copper contain 80% and 89% of copper respectively. Show that this data is in accordance with law of multiple proportions.

The common salt was obtained from two different sources. In one sample, the percentage of chlorine was found to be 60.75 %. In the second sample, 3.888 g of chlorine were present in 6.4 g of the salt. Show that these data are in accordance to the law of constant proportion.

Ammonia contains 82.35% of nitrogen and 17.65% of hydrogen. Water contains 88.90% of oxygen . Nitrogen trioxide contains 63.15% of oxygen and 36.85% of nitrogen. Show by calculations from these data which law of chemicmal combination is verified.