Find the normality of `H_(2) SO_(4)` having 50 milli equivalents in 2 litres.

Explanation

To find the normality of \( H_2SO_4 \) with 50 milli equivalents in 2 liters, we can follow these steps:

### Step 1: Understand the Definition of Normality
Normality (N) is defined as the number of equivalents of solute per liter of solution. The formula for calculating normality is:

\[ \text{Normality (N)} = \frac{\text{Number of equivalents}}{\text{Volume of solution in liters}} \]

### Step 2: Convert Milli Equivalents to Equivalents
Given that we have 50 milli equivalents (mEq) of \( H_2SO_4 \), we need to convert this to equivalents.

1 equivalent = 1000 milli equivalents

So,

\[ 50 \, \text{mEq} = \frac{50}{1000} \, \text{Eq} = 0.05 \, \text{Eq} \]

### Step 3: Calculate the Normality
Now, we can use the formula for normality. We have the number of equivalents (0.05 Eq) and the volume of the solution (2 L):

\[ \text{Normality (N)} = \frac{0.05 \, \text{Eq}}{2 \, \text{L}} = 0.025 \, \text{N} \]

### Final Answer
The normality of \( H_2SO_4 \) is \( 0.025 \, \text{N} \).

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