Which of the statement are true??

Options

A. (a) The equivalent weight of `Ca_(3)(PO_(4))_(2)` is `Mw//6`.
B. The equivalent weight of `Na_(3)PO_(4).12H_(2)O` is `Mw//3`.
C. The equivalent weight of `K_(2) SO_(4)` is `Mw//2`.
D. The equivalent weight of potas alum `K_(2)SO_(4)Al_(2)(SO_(4))_(3).24H_(2) O` is `Mw//8`

Explanation

To determine which statements are true regarding the equivalent weight of various compounds, we will analyze each option step by step.

### Step-by-Step Solution:

1. **Understanding Equivalent Weight**:
- The formula for equivalent weight is:
\[ \text{Equivalent Weight} = \frac{\text{Molecular Weight (Mw)}}{\text{N Factor}} \]
- The N factor is defined as the total positive or negative charge present in the compound.

2. **Analyzing Option A: Calcium Phosphate (Ca₃(PO₄)₂)**:
- Calcium phosphate contains:
- 3 Calcium ions (Ca²⁺) contributing a total positive charge of \(3 \times 2 = +6\).
- 2 Phosphate ions (PO₄³⁻) contributing a total negative charge of \(2 \times -3 = -6\).
- Total charges: +6 (positive) and -6 (negative).
- Therefore, the N factor = 6.
- Equivalent weight:
\[ \text{Equivalent Weight} = \frac{\text{Mw}}{6} \]
- This option is **true**.

3. **Analyzing Option B: Sodium Phosphate (Na₃PO₄·12H₂O)**:
- Sodium phosphate contains:
- 3 Sodium ions (Na⁺) contributing a total positive charge of \(3 \times 1 = +3\).
- 1 Phosphate ion (PO₄³⁻) contributing a total negative charge of -3.
- Total charges: +3 (positive) and -3 (negative).
- Therefore, the N factor = 3.
- Equivalent weight:
\[ \text{Equivalent Weight} = \frac{\text{Mw}}{3} \]
- This option is **true**.

4. **Analyzing Option C: Potassium Sulfate (K₂SO₄)**:
- Potassium sulfate contains:
- 2 Potassium ions (K⁺) contributing a total positive charge of \(2 \times 1 = +2\).
- 1 Sulfate ion (SO₄²⁻) contributing a total negative charge of -2.
- Total charges: +2 (positive) and -2 (negative).
- Therefore, the N factor = 2.
- Equivalent weight:
\[ \text{Equivalent Weight} = \frac{\text{Mw}}{2} \]
- This option is **true**.

5. **Analyzing Option D: Potash Alum (K₂SO₄·Al₂(SO₄)₃·24H₂O)**:
- Potash alum contains:
- 2 Potassium ions (K⁺) contributing a total positive charge of \(2 \times 1 = +2\).
- 2 Aluminum ions (Al³⁺) contributing a total positive charge of \(2 \times 3 = +6\).
- 4 Sulfate ions (SO₄²⁻) contributing a total negative charge of \(4 \times -2 = -8\).
- Total charges: +8 (positive) and -8 (negative).
- Therefore, the N factor = 8.
- Equivalent weight:
\[ \text{Equivalent Weight} = \frac{\text{Mw}}{8} \]
- This option is **true**.

### Conclusion:
All four statements regarding the equivalent weights of the given compounds are true.