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A bulb contains 1.6 g of O(2) contains....

A bulb contains `1.6 g` of `O_(2)` contains.

A

0.05 mol of `O_(2)`

B

`3.011 xx 10^(22)` molecules of `O_(2)`

C

`1.12 L` of `O_(2)` at `STP`

D

`1.22 L` of `O_(2)` at `STP`

Text Solution

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The correct Answer is:
To solve the problem of determining the properties of 1.6 g of \( O_2 \) in a bulb, we will follow these steps: ### Step 1: Calculate the number of moles of \( O_2 \) To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \] Given mass of \( O_2 = 1.6 \, g \) The molar mass of \( O_2 \) (oxygen) is \( 32 \, g/mol \) (since the atomic mass of oxygen is approximately \( 16 \, g/mol \) and there are two oxygen atoms in \( O_2 \)). Now, substituting the values: \[ \text{Number of moles} = \frac{1.6 \, g}{32 \, g/mol} = 0.05 \, mol \] ### Step 2: Calculate the number of molecules of \( O_2 \) To find the number of molecules, we use Avogadro's number (\( N_A \)), which is approximately \( 6.022 \times 10^{23} \, molecules/mol \). Using the formula: \[ \text{Number of molecules} = \text{Number of moles} \times N_A \] Substituting the values: \[ \text{Number of molecules} = 0.05 \, mol \times 6.022 \times 10^{23} \, molecules/mol = 3.011 \times 10^{22} \, molecules \] ### Step 3: Calculate the volume of \( O_2 \) at STP At Standard Temperature and Pressure (STP), 1 mole of any gas occupies \( 22.4 \, L \). Using the formula: \[ \text{Volume at STP} = \text{Number of moles} \times 22.4 \, L/mol \] Substituting the values: \[ \text{Volume at STP} = 0.05 \, mol \times 22.4 \, L/mol = 1.12 \, L \] ### Step 4: Calculate the volume of \( O_2 \) at SATP At Standard Ambient Temperature and Pressure (SATP), 1 mole of any gas occupies \( 24.4 \, L \). Using the formula: \[ \text{Volume at SATP} = \text{Number of moles} \times 24.4 \, L/mol \] Substituting the values: \[ \text{Volume at SATP} = 0.05 \, mol \times 24.4 \, L/mol = 1.22 \, L \] ### Summary of Results - Moles of \( O_2 \): \( 0.05 \, mol \) - Molecules of \( O_2 \): \( 3.011 \times 10^{22} \, molecules \) - Volume of \( O_2 \) at STP: \( 1.12 \, L \) - Volume of \( O_2 \) at SATP: \( 1.22 \, L \)

To solve the problem of determining the properties of 1.6 g of \( O_2 \) in a bulb, we will follow these steps: ### Step 1: Calculate the number of moles of \( O_2 \) To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} ...
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