Which of the following solution contains same molar concentration?

Options

A. `166 g. KI//L` solution.
B. `33.0 g (NH_(4))_(2) SO_(4)` in `200 mL` solution
C. `25.0 g CuSO_(4).5H_(2) O` in `100 mL` solution
D. `27.0 mg Al^(3+)` per `mL` solution.

Explanation

To determine which of the given solutions contains the same molar concentration, we will calculate the molarity of each solution step by step.

### Step 1: Calculate Molarity of KI
1. **Given Data**:
- Mass of KI = 166 g
- Molar mass of KI = 166 g/mol
- Volume = 1 L (or 1000 mL)

2. **Formula for Molarity (M)**:
\[ M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \]

3. **Calculate Moles of KI**:
\[ \text{Moles of KI} = \frac{\text{mass}}{\text{molar mass}} = \frac{166 \text{ g}}{166 \text{ g/mol}} = 1 \text{ mol} \]

4. **Calculate Molarity**:
\[ M = \frac{1 \text{ mol}}{1 \text{ L}} = 1 \text{ M} \]

### Step 2: Calculate Molarity of NH4SO4
1. **Given Data**:
- Mass of NH4SO4 = 33 g
- Molar mass of NH4SO4 = 132 g/mol
- Volume = 200 mL (or 0.2 L)

2. **Calculate Moles of NH4SO4**:
\[ \text{Moles of NH4SO4} = \frac{33 \text{ g}}{132 \text{ g/mol}} = 0.25 \text{ mol} \]

3. **Calculate Molarity**:
\[ M = \frac{0.25 \text{ mol}}{0.2 \text{ L}} = 1.25 \text{ M} \]

### Step 3: Calculate Molarity of CuSO4.5H2O
1. **Given Data**:
- Mass of CuSO4.5H2O = 25 g
- Molar mass of CuSO4.5H2O = 250 g/mol
- Volume = 100 mL (or 0.1 L)

2. **Calculate Moles of CuSO4.5H2O**:
\[ \text{Moles of CuSO4.5H2O} = \frac{25 \text{ g}}{250 \text{ g/mol}} = 0.1 \text{ mol} \]

3. **Calculate Molarity**:
\[ M = \frac{0.1 \text{ mol}}{0.1 \text{ L}} = 1 \text{ M} \]

### Step 4: Calculate Molarity of Al3+
1. **Given Data**:
- Mass of Al3+ = 27 mg = 0.027 g
- Molar mass of Al3+ = 27 g/mol
- Volume = 1 mL (or 0.001 L)

2. **Calculate Moles of Al3+**:
\[ \text{Moles of Al3+} = \frac{0.027 \text{ g}}{27 \text{ g/mol}} = 0.001 \text{ mol} \]

3. **Calculate Molarity**:
\[ M = \frac{0.001 \text{ mol}}{0.001 \text{ L}} = 1 \text{ M} \]

### Conclusion
- Molarity of KI = 1 M
- Molarity of NH4SO4 = 1.25 M
- Molarity of CuSO4.5H2O = 1 M
- Molarity of Al3+ = 1 M

**Final Answer**: The solutions that contain the same molar concentration are KI, CuSO4.5H2O, and Al3+ (1 M each).