An excellent solution for cleaning grease stains from cloth of leather consists of the folllowing components: `C Cl_(4)` (80% by volume), ligroin (16%) and amyl alcohol (4%) How many `mL` of each should to taken to make up `80 mL` of solution?

Options

A. `64 mL C Cl_(4)`
B. `12.8 mL` ligroin
C. `32 mL` of amy alcohol
D. `3.2 mL` of amyl alcohol

Explanation

To solve the problem of how many mL of each component should be taken to make up 80 mL of the cleaning solution, we will follow these steps:

### Step 1: Calculate the volume of CCl₄
Given that CCl₄ constitutes 80% of the solution, we can calculate its volume as follows:

\[ \text{Volume of CCl}_4 = 80 \, \text{mL} \times \frac{80}{100} = 64 \, \text{mL} \]

### Step 2: Calculate the volume of ligroin
Ligroin makes up 16% of the solution. We calculate its volume similarly:

\[ \text{Volume of ligroin} = 80 \, \text{mL} \times \frac{16}{100} = 12.8 \, \text{mL} \]

### Step 3: Calculate the volume of amyl alcohol
Amyl alcohol constitutes 4% of the solution. We calculate its volume as follows:

\[ \text{Volume of amyl alcohol} = 80 \, \text{mL} \times \frac{4}{100} = 3.2 \, \text{mL} \]

### Summary of Volumes
- Volume of CCl₄: **64 mL**
- Volume of ligroin: **12.8 mL**
- Volume of amyl alcohol: **3.2 mL**

### Final Answer
To prepare 80 mL of the solution, you should take:
- **64 mL of CCl₄**
- **12.8 mL of ligroin**
- **3.2 mL of amyl alcohol**

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