A sample contains a mixtrure of `NaHCO_(3)` and `Na_(2)CO_(3)`.
`HCl` is added to `15.0 g`.of the sample, yielding `11.0 g` of `NaCl`. What percent of the sample is `Na_(2)CO_(3)`?
`[{:("Reaction are"),(Na_(2)CO_(3) + 2HCl rarr 2NaCl + CO_(2) + H_(2) O),(NaHCO_(2) + HCl rarr NaCL + CO_(2) + H_(2) O):}]`
`Mw "of" NaCl = 58.5, Mw "of" NaHCO_(3) = 84, Mw "of" Na_(2)CO_(3) = 106 g mol^(-1)`

Explanation

To solve the problem step by step, we will follow the outlined approach:

### Step 1: Define Variables
Let:
- \( x \) = mass of \( \text{Na}_2\text{CO}_3 \) in grams
- Therefore, the mass of \( \text{NaHCO}_3 \) will be \( 15 - x \) grams (since the total sample mass is 15 g).

### Step 2: Calculate Moles of NaCl Produced
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