The specific gravity of a salt solution is 1.025. If `V mL` of water is added to `1 L` of this solution to make its density `1.02 g mL^(-1)`, what value of `V` in `mL` approxmately?

Explanation

To solve the problem, we need to find the volume \( V \) of water added to a salt solution to achieve a specific density. Here’s a step-by-step solution:

### Step 1: Understand the Given Information
- The specific gravity of the salt solution is \( 1.025 \).
- The volume of the salt solution is \( 1 \, \text{L} = 1000 \, \text{mL} \).
- We need to find the volume \( V \) of water added to achieve a new density of \( 1.02 \, \text{g/mL} \).

### Step 2: Calculate the Mass of the Salt Solution
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