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Br2 undergoes disproportionation reactio...

`Br_2` undergoes disproportionation reaction in basic medium to give `Br^(ɵ)` ion and `BrO_3^(ɵ)` (bromate) ion in reduction and oxidation reaction.

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To solve the problem of the disproportionation reaction of \( Br_2 \) in a basic medium, we will break it down into a series of steps. ### Step 1: Write the Half-Reactions The first step is to identify the half-reactions for the reduction and oxidation processes. 1. **Reduction Half-Reaction**: \[ Br_2 + 2e^- \rightarrow 2Br^- ...
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18 " mL of " 1.0 M Br_(2) solution undergoes complete disproportionation in basic medium to Br^(The hardness of water in terms of ) and BrO_(3)^(ɵ) . Then the resulting solution required 45 " mL of " As^(3+) solution to reduce BrO_(3)^(ɵ) to Br^(ɵ) . As^(3+) is oxidised to As^(5+) which statements are correct?

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Which of the following substances undergo(s) disproportionation reactions under basic medium?

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Redox is a reaction in which both oxidation and reduction will take place simultaneously . It is obvious that if one substance gives electron there must be another substance to accept these electrons . In some reactions, same substance is reduced as well as oxidised, these reactions are termed as disproportionation reactions. For calculating equivalent mass in redox reaction change in oxidtaion number is realted to n-factor which is reciprocal of molar ratio. This reaction is an example of Br_(2) + OH^(-) to BrO_(3)^(-) + H_(2)O + Br^(-)

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