Upon heating 1 L of 2 N HCl solution, 36.5 g of HCl is lost and the volume of solution resuces to 800 mL. Calculate . (a). The normality of the resultant solution.

Explanation

To solve the problem step by step, we will calculate the normality of the resultant HCl solution after heating.

### Step 1: Understand the initial conditions
We have a 1 L solution of 2 N HCl. The normality (N) is given as 2 N, which means there are 2 equivalents of HCl in 1 L of solution.

### Step 2: Calculate the initial amount of HCl
To find the total amount of HCl in grams in the initial solution, we can use the formula:
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