How many moles of `HgI_4^(2-)` will be formed when 1 " mol of "`Hg^(2+)` and 1 mol `I^(ɵ)` react according to the following equation?
`Hg^(2+)+4I^(ɵ)toHgI_4^(2-)`
(a). 1 mol
(b). 0.5 mol
(c). 0.25 mol
(d). 2 mol

Explanation

To determine how many moles of `HgI_4^(2-)` will be formed when 1 mole of `Hg^(2+)` reacts with 1 mole of `I^(-)`, we can follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction is:
\[ \text{Hg}^{2+} + 4\text{I}^- \rightarrow \text{HgI}_4^{2-} \]

### Step 2: Identify the stoichiometry of the reaction
From the balanced equation, we can see that:
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