What weight of `NaHSO_3` is required to react with 100 " mL of " solution containing 0.33 g of `NaIO_3` according to the following reaction:
`IO_3^(ɵ)+HSO_3^(ɵ)toI^(ɵ)+SO_3^(2-)`
(a). `0.52g`
(b). `5.2 g`
(c). `1.04g`
(d). `10.4g`

Explanation

To solve the problem of determining the weight of NaHSO₃ required to react with 100 mL of a solution containing 0.33 g of NaIO₃, we can follow these steps:

### Step 1: Determine the Molar Mass of NaIO₃
The molar mass of NaIO₃ (Sodium Iodate) can be calculated as follows:
- Na: 23 g/mol
- I: 127 g/mol
- O₃: 3 × 16 g/mol = 48 g/mol

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