KI reacts with`H_2SO_4` producing `I_2` and `H_2S`. The volume of 0.2 M `H_2SO_4` required to produce 0.1mol of `H_2S` is
(a). 2.5 L
(b). 3.8 L
(c). 4 L
(d). 5 L

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between KI and H₂SO₄ can be represented as:
\[ 8 \text{KI} + 5 \text{H}_2\text{SO}_4 \rightarrow 4 \text{K}_2\text{SO}_4 + 4 \text{I}_2 + 4 \text{H}_2\text{S} + 4 \text{H}_2\text{O} \]

### Step 2: Determine the mole ratio
From the balanced equation, we see that:
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