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4 " mol of "a solution A^(n+) requires 1...

4 " mol of "a solution `A^(n+)` requires 1.6 " mol of "`MnO_4^(-)` ions for the oxidation of `A^(n+)` to `AO_3^(ɵ)` in acidic medium the value of n is (a). 1
(b). 2.
(c). 3.
(d). 4.

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To solve the problem, we need to determine the value of \( n \) in the oxidation reaction of \( A^{n+} \) to \( AO_3^{\circ} \) using \( MnO_4^{-} \) ions in an acidic medium. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction involves the oxidation of \( A^{n+} \) to \( AO_3^{\circ} \). We need to find out how many electrons are involved in this reaction. 2. **Determine the Oxidation State of A**: ...
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2.68xx10^(-3) moles of solution containing anion A^(n+) require 1.61xx10^(-3) moles of MnO_(4)^(-) for oxidation of A^(n+) to AO_(3)^(-) in acidic medium. What is the value of n ?

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