`1.0 g` of metal nitrate gave `0.86 g` of metal sulphate. Calculate equivalent weight of metal.

Explanation

`Ew(NO_3^(ɵ))=(Mw(NO_3^(ɵ)))/("Charge")=(14+3xx16)/(1)=62`
`Ew(SO_4^(2-))=(Mw(SO_4^(2-)))/("Charge")=(32xx4xx16)/(2)=(96)/(2) =48`
Equivalent of metal nitrate`=`Equivalent of metal sulphate
`("Weight of metal nitrate")/(Ew(M)+Ew(NO_3^(ɵ))=("Weight of metal sulphate")/(Ew(M)+Ew(SO_4^(2-))`
`(1.0)/(E+62)=(0.86)/(E+48)`
`E=38`