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Calculate (a) normality (b) molarity (c)...

Calculate (a) normality (b) molarity (c) strength in `gL^(-1)` and (d) percentage strength of 10 volume strength of `H_2O`

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To solve the question regarding the calculation of normality, molarity, strength in g/L, and percentage strength of 10 volume strength of H₂O₂ (hydrogen peroxide), we will follow these steps: ### Step 1: Understanding Volume Strength Volume strength of a solution indicates the volume of gas produced at STP (Standard Temperature and Pressure) when a certain volume of the solution is completely decomposed. For H₂O₂, 1 volume strength corresponds to 1 mL of the solution producing 1 mL of O₂ gas at STP. Given that we have a 10 volume strength of H₂O₂, it means that 1 L of this solution will produce 10 L of O₂ gas. ### Step 2: Calculate Normality ...
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The strength of H_(2)O_(2) is expressed in many ways like molarity , normality , % strength and volume strengths But out of all these form of strengths , volume strength has great significance for chemical reactions . This decomposition of H_(2)O_(2) is shown as under H_(2)O_(2)(l) to H_(2)O(l) + (1)/(2)O_(2)(g) 'x' volume strength of H_(2)O_(2) means one volume (litre or ml) of H_(2)O_(2) releases x volume (litre or ml) of O_(2) at NTP . 1 litre H_(2)O_(2) release x litre of O_(2) at NTP =(x)/(22.4) moles of O_(2) From the equation , 1 mole of O_(2) produces from 2 moles of H_(2)O_(2) . (x)/(22.4) moles of O_(2) produces from 2xx(x)/(22.4) moles of H_(2)O_(2) =(x)/(11.2) moles of H_(2)O_(2) So, molarity of H_(2)O_(2)=((x)/(11.2))/(1)=(x)/(11.2)M Normality =n-factor xx molarity =2xx(x)/(11.2)=(x)/(5.6) N What is the percentage strength of "15 volume" H_(2)O_(2) ?

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