1.84 g of `CaCO_3` and `MgCO_3` were treated with `50 mL` of 0.8 HCl solution. Calculate the percentage of `CaCO_3` and `MgCO_3`.

Explanation

To solve the problem of determining the percentage of `CaCO3` and `MgCO3` in a mixture weighing 1.84 g that was treated with 50 mL of 0.8 M HCl solution, we can follow these steps:

### Step-by-Step Solution:

1. **Define Variables:**
Let the weight of `CaCO3` in the mixture be \( X \) grams. Therefore, the weight of `MgCO3` will be \( 1.84 - X \) grams.

2. **Write the Reaction:**
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