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5.5 g of a mixutre of FeSO4.7H2O and Fe2...

5.5 g of a mixutre of `FeSO_4.7H_2O` and `Fe_2(SO_4)_3.9H_2O` requires 5.4 " mL of " `0.1 N KMnO_4` solution for complete oxidation. Calculate the number of gram moles of hydrated ferric sulphate in the mixture.

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To solve the problem step by step, we will follow the stoichiometric principles and the information provided in the question. ### Step 1: Understand the Reaction The reaction involves the oxidation of ferrous ions (from `FeSO4.7H2O`) to ferric ions (from `Fe2(SO4)3.9H2O`) by potassium permanganate (`KMnO4`). The balanced half-reactions are: - For `KMnO4`: \[ \text{Mn}^{7+} + 5e^- \rightarrow \text{Mn}^{2+} \] ...
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