30 " mL of " a solution containing `9.15gL^(-1)`
of an oxalate `K_(x)H_(y)(C_2O_4)_2.nH_2O` required for titration 27 " mL of " 0.12 N NaOH and 36 " mL of " 0.12 N `KMnO_4` for oxidation Find x,y,z. and n.

Explanation

To solve the problem, we need to determine the values of \( x \), \( y \), \( z \), and \( n \) in the formula \( K_xH_y(C_2O_4)_2 \cdot nH_2O \) based on the titration data provided.

### Step-by-Step Solution:

1. **Determine the Molarity of the Oxalate Solution:**
Given that the solution has a concentration of \( 9.15 \, \text{g/L} \), we can convert this to molarity. The molar mass of oxalic acid \( (C_2O_4) \) is approximately \( 90 \, \text{g/mol} \).
\[
\text{Molarity} = \frac{\text{grams per liter}}{\text{molar mass}} = \frac{9.15 \, \text{g/L}}{90 \, \text{g/mol}} = 0.10167 \, \text{mol/L}
...