1.5 g of a mixture containing `As_2O_5`, `Na_2HAsO_3`, and some inert impurities is dissolved in water, and the solution is kept neutral by adding excess of `NaHCO_3`. The solution when titrated with 0.1 M `I_2` required 35.0 nL of it for complete titration. The solution is then acidified and excess of KI is added to it. The `I_2` liberated required `35.0mL` of `0.3 M Na_2S_2O_3` solution for complete titration. Find the percentage composition of the mixture (Atomic mass of As is 75, Na is 23 and O is 16.)

Explanation

To solve the problem step-by-step, we will analyze the reactions involved and perform calculations based on the given data.

### Step 1: Understand the Mixture
The mixture contains:
- \( As_2O_5 \)
- \( Na_2HAsO_3 \)
- Inert impurities

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