500 " mL of " a solution contains 2.65 g of `Na_2CO_3` and 4 g of `NaOH`. 20 " mL of " this solution titrated each time against `(N)/(10)H_2SO_4`. Find out the titre value if (a). Methyl orange is taken as an indicator
(b). Phenolphthalein is taken as indicator.

Explanation

To solve the problem step by step, we will follow the given information and apply stoichiometric principles.

### Step 1: Calculate the concentration of Na2CO3 and NaOH in the solution.
1. **Na2CO3**:
- Given mass = 2.65 g in 500 mL.
- To find the mass in 1 L (1000 mL):
\[
\text{Mass in 1 L} = \frac{2.65 \, \text{g}}{500 \, \text{mL}} \times 1000 \, \text{mL} = 5.3 \, \text{g}
...