95 " mL of " a mixture of a gaseous organic compound A and just sufficient amount of oxygen required for the complete yields on burning 40 " mL of " `CO_2` and 70 " mL of " water vapour along with 10 " mL of " nitrogen,volumes measured at the same temperature and pressure. Compound A contains corbon, hydrogen, and nitrogen only as the constituent elements. Calculate.
(a). The volume of `O_2` required for complete combustion
(b). The molecular formula of A.

Explanation

`C_(x)H_(y)N_(z)+(x+(y)/(4))O_2toxCO_2+(y)/(2)H_2O+(z)/(2)N_2`
`a(x+(y)/(4))axa[(y)/(2)xxa](z)/(2)xxamL`
According to the question.
`{:(ax=40mL),(a(y)/(2)=70mL),(a(z)/(2)=10mL),(ax=40mL),(axx2=40mL),(a=20mL):}]^(becausex:(y)/(2):(z)/(2)-=4:7:1`
or
`2:y:z=8:14:2`
`therefore2x=8`
`x=3`
`thereforex:y:z=4:14:2 or 2:7:1`
Formula `=C_2H_7Nbecausex=2`