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16 " mL of " a gaseous compound C(n)H(3n...

16 " mL of " a gaseous compound `C_(n)H_(3n)O_(m)` was mixed with 60 " mL of " `O_2` and sparked. The gas mixture on cooling occupied 44 mL. After treatment with NaOH solution, the volume of gas remaining was 12 mL. Deduce the formula of the compound.

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To deduce the formula of the compound \( C_nH_{3n}O_m \) from the given information, we will follow these steps: ### Step 1: Understand the Reaction The gaseous compound \( C_nH_{3n}O_m \) reacts with oxygen \( O_2 \) to produce carbon dioxide \( CO_2 \) and water \( H_2O \). The balanced reaction can be expressed as: \[ C_nH_{3n}O_m + O_2 \rightarrow nCO_2 + \frac{3n}{2}H_2O \] ...
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