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In basic solution CrO4^(2-) oxidises S2O...

In basic solution `CrO_4^(2-)` oxidises `S_2O_3^(2-)` to form `[Cr(OH)_4]^(ɵ)` and `SO_4^(2-)` How many millilitres of 0.154 `M Na_2CrO_4` are required to react with 40.0 " mL of " 0.246 M `Na_2S_2O_3`.

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`3e^(-)+CrO_4^(2-)to[Cr(OH)^(4)]^(ɵ)`
`S_2O_3^(2-)to2SO_4^(2-)+8e^(-)`
`N_1V_1=N_2V_2`
`3xx0.154xxV_1=8xx0.246xx40`
`thereforeV_1=170mL`
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