Number of ions present in `2.0 "litre"` of a solution of `0.8 M K_(4)Fe(CN)_(6)` is:

Explanation

To find the number of ions present in 2.0 litres of a solution of 0.8 M K₄Fe(CN)₆, we can follow these steps:

### Step 1: Calculate the number of moles of K₄Fe(CN)₆
To find the number of moles, we use the formula:
\[ \text{Moles} = \text{Molarity} \times \text{Volume (L)} \]
Given:
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