A 36 mL mixture of an alkene and propane required 171 " mL of " `O_2` for complete combustion and yielded 109 " mL of " `CO_2` (all volume measured at same temperature and presasure). Calculate the molecular formula of olefin and composition of the mixture by volume.

Explanation

To solve the problem step by step, we will analyze the combustion of the alkene and propane mixture, calculate the volumes of each component, and derive the molecular formula of the alkene.

### Step 1: Define the Variables
Let:
- \( x \) = volume of alkene (in mL)
- \( 36 - x \) = volume of propane (in mL)

### Step 2: Write the Combustion Reactions
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