What volume of 0.1 M `KMnO_4` is required to oxidise " 5mg of `FeC_2O_4` (ferrous oxalate) in acidic medium?

Explanation

To solve the problem of determining the volume of 0.1 M `KMnO_4` required to oxidize 5 mg of `FeC_2O_4` (ferrous oxalate) in an acidic medium, we can follow these steps:

### Step 1: Calculate the Equivalent Weight of `FeC_2O_4`
1. **Determine the molecular weight of `FeC_2O_4`:**
- The molecular weight of `FeC_2O_4` can be calculated as follows:
- Iron (Fe) = 55.85 g/mol
- Carbon (C) = 12.01 g/mol (2 atoms)
- Oxygen (O) = 16.00 g/mol (4 atoms)
...