1.67 g mixture of Al and Zn was completely dissolved in acid and evolved 1.69 L of `H_2` at STP. Calculate the weight Al and Zn in the mixture.

Explanation

Let the weight of Al be x g and weight of Zn be `(1.67 -x)` g .
" Eq of "`Al =(x)/((27)/(3))`
" Eq of "`Zn=((1.67-x))/((65.4)/(2))`
" Eq of "`H_2=(1.69)/(11.2)`
`therefore(x)/((27)/(3))+((1.67-x))/((65.4)/(2))=(1.69)/(11.2)`
`3xx65.4x +1.67xx2xx27-2xx27=(1.69)/(11.2)xx27xx65.4`
`196.2xx-90.18-54x=266.446`
`thereforex=1.239g`