The vapoour density of a mixture containing `NO_(2)` and `N_(2)O_(4)` is 38.3 at 300 K. the number of moles of `NO_(2)` in 100 g of the mixture is approximately

Explanation

Molecular weight of the mixture`=38.3xx2=76.6`
Molecular weight of `NO_2=46 and N_2O_4=92`
Let the number of moles of `NO_2` be x.
Number of moles of `N_2O_4=(100-46x)/(92)`
`x+(100-46x)/(92)=(100)/(76.6)impliesx=0.438mol`