`CN^(ɵ)` is oxidised by a strong oxidising agent to `NO_3^(ɵ)` and `CO_2` or `CO_3^(2-)` depending upon the acidity of the reaction mixture. `HNO_3` a strong oxidising agent is reduced by a moderate reducing agent to NO. Write the balanced equation of `HNO_3` with KCN.
`CH^(ɵ)toCO_2+NO_3^(ɵ)`
`NO_3^(ɵ)NO`
If this reaction is carried out, what safety precautions are required?

Explanation

To balance the reaction of potassium cyanide (KCN) with nitric acid (HNO₃), we need to follow these steps:

### Step 1: Write the unbalanced equation
The initial unbalanced reaction can be written as:
\[ \text{CN}^- + \text{HNO}_3 \rightarrow \text{CO}_2 + \text{NO} + \text{H}_2\text{O} \]

### Step 2: Identify oxidation states
- In CN⁻, the oxidation state of carbon (C) is -4 and nitrogen (N) is +3.
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