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30 " mL of " a solution of mixture of Na...

30 " mL of " a solution of mixture of `Na_2CO_3` and `NaHCO_3` required 12 " mL of " 0.05 M `H_2SO_4` using phenolphthalein as indicator. With methyl orange 30 " mL of " the same solution required 40 " mL of " same `H_2SO_4`. Calculate the amount of `Na_2CO_3` and `NaHCO_3` per litre in the mnixture.

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To solve the problem of determining the amounts of \( \text{Na}_2\text{CO}_3 \) and \( \text{NaHCO}_3 \) in a mixture based on titration data, we can follow these steps: ### Step 1: Calculate the milliequivalents of \( \text{H}_2\text{SO}_4 \) used with phenolphthalein Using the formula: \[ \text{mEq of } H_2SO_4 = \text{Volume (L)} \times \text{Molarity (mol/L)} \times \text{n factor} \] Given: ...
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