Calculate the weight of `MnO_(2)` and the volume of HCl of specific gravity 1.2 g g `mL^(-1)` and `5%` by weight needed to produce 1.12 L of `Cl_(2)` at STP by the reaction `MnO_(2)+4"HCl"toMnCl_(2)+3H_(2)O+Cl_(2)`

Explanation

To solve the problem of calculating the weight of `MnO2` and the volume of HCl needed to produce 1.12 L of `Cl2` at STP, we will follow these steps:

### Step 1: Calculate the Normality of HCl
The normality (N) of HCl can be calculated using the formula:
\[ N = \frac{\text{Percentage by weight} \times 10 \times \text{Specific Gravity}}{\text{Equivalent Weight of HCl}} \]
Given:
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