Chile salt peter a source of `NaNO_(3)` also contains `NaIO_(3)` the `NaIO_(3)` is a source of `I_(2)` produced as shown in the following equation:
Step I: `IO_(3)^(ɵ)+3HSO_(3)^(ɵ)+3SO_(4)^(2-)`
Step II: `5I^(ɵ)+IO_(3)^(ɵ)+6H^(o+)to3I_(2)(s)+3H_(2)O`
One litre sample of chile salt peter solution containing 6.6 g `NaIO_(3)` is treated with `NaHSO_(3)` Now an additional amount of same solution is added to the reaction mixture to bring about the second titration. Calculate the weight of `NaHSO_(3)` requried in step I and what additional volume of chile salt peter mist be added in step II to bring out complete conversion of `I^(ɵ)` to `I_(2)`.

Explanation

To solve the problem step by step, we will follow the reactions provided and calculate the required amounts of `NaHSO3` and the additional volume of `NaIO3` needed.

### Step 1: Calculate the moles of `NaIO3`

Given:
- Mass of `NaIO3` = 6.6 g
- Molar mass of `NaIO3` = 85 g/mol (Na = 23, I = 127, O = 16*3)

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