3.0 g sample of KOCl and `CaOCl_(2)` is dissolved in water to prepare 100 mL solution, which requried 100 " mL of " 0.15 M acidified `K_(2)C_(2)O_(4)`. For the point. The clear solution is now treated with excess of `AgNO_(3)` solution which precipitates 2.87 g of `AgCl`. Calculate the mass percentage of KOCl and `CaOCl_(2)` in the mixture.

Explanation

To solve the problem, we need to determine the mass percentage of KOCl and Ca(OCl)2 in a 3.0 g sample that was dissolved in water. The solution reacts with K2C2O4 and AgNO3, leading to the precipitation of AgCl. Here’s a step-by-step breakdown of the solution:

### Step 1: Determine the moles of K2C2O4 used
Given:
- Volume of K2C2O4 solution = 100 mL = 0.1 L
- Molarity of K2C2O4 = 0.15 M

Using the formula:
...