100 mL of 0.01 M `KMnO_(4)` oxidised 100 mL `H_(2)O_(2)` in acidic medium. The volume of same `KMnO_(4)` required in strong alkaline medium to oxidise 100 mL of same `H_(2)O_(2)` will be:

Options

A. `(100)/(3)mL`
B. `(500)/(3)mL`
C. `(300)/(5)mL`
D. None

Answer

B

Explanation

`MnO_(4)^(ɵ)+5e^(-)toMn^(2+)` (acidic)
`MnO_(4)^(ɵ)+3e^(-)toMnO_(2)` (basic)
`100 mL H_(2)O_(2)-=100xx5N MnO_(4)^(ɵ)-=Vxx3NMnO_(2)`
`V=(500)/(3)mL`