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How many moles of HgI4^(2-) will be form...

How many moles of `HgI_4^(2-)` will be formed when 1 " mol of "`Hg^(2+)` and 1 mol `I^(ɵ)` react according to the following equation?
`Hg^(2+)+4I^(ɵ)toHgI_4^(2-)`
(a). 1 mol
(b). 0.5 mol
(c). 0.25 mol
(d). 2 mol

A

1 mol

B

0.5 mol

C

0.25 mol

D

2 mol

Text Solution

Verified by Experts

The correct Answer is:
C
`I^(ɵ)` is limiting reagent so one mole `I^(ɵ)` will give `(1)/(4)` mol or `0.25` moles of `Hgl_(4)^(2-)`
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