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Equivalent mass of KMnO4 in acidic, stro...

Equivalent mass of `KMnO_4` in acidic, strongly basic and neutral are in the ratio of

A

`3:4:15`

B

`5:3:1`

C

`5:1:13`

D

`3:15:5`

Text Solution

Verified by Experts

The correct Answer is:
A

(i). `MnO_(4)^(ɵ)toMn^(2+) (acidic) Ew=(Mw)/(5)`
(ii). `MnO^(4)^(ɵ)toMnO_(2) (neutral) Ew=(Mw)/(3)`
(iii). `MnO_(4)^(ɵ)toMnO_(4)^(2-) (basic) Ew=(Mw)/(1)`
Ratio is `(1)/(5):(1)/(3):(1)/(1)=3:5:15`
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