In the reaction `A^(+x) + MnO_(4)^() to AO_(3)^() + Mn^(++) +(1)/(2)O, ` if one mole fo `MnO_(4)^()` oxidises 1.67 moles of `A^(+x) ` to `AO_(3)^()` , then what will be the value of x ?

Options

A. 2
B. 3
C. 4
D. 5

Answer

A

Explanation

`M^(x+)+MnO_(4)^(ɵ)toMO_(3)^(ɵ)+Mn^(2+)`
`MnO_(4)^(ɵ)+8H^(o+)+5e^(-)toMn^(2+)+4H_(2)O`
`M^(x+)+3H_(2)OtoMO_(3)^(ɵ)+6H^(o+)+(5-x)e^(-)`
`m" Eq of "MnO_(4)^(2-)-=m" Eq of "M^(x+)`
`1xx5-=[1.67xx(5-x)]implies5-x=3impliesx=2`