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In basic solution CrO4^(2-) oxidises S2O...

In basic solution `CrO_4^(2-)` oxidises `S_2O_3^(2-)` to form `[Cr(OH)_4]^(ɵ)` and `SO_4^(2-)` How many millilitres of 0.154 `M Na_2CrO_4` are required to react with 40.0 " mL of " 0.246 M `Na_2S_2O_3`.

A

`240.2mL`

B

`24.02mL`

C

`266.65mL`

D

`26.67`mL

Text Solution

Verified by Experts

The correct Answer is:
C
`S_(2)O_(3)^(2-)to2SO_(4)^(2-)+8e^(-)`
`3e^(-)+CrO_(4)^(2-)to[Cr(OH)_(4)]^(ɵ)`
`CrO_(4)^(2-)-=S_(2)O_(3)^(2-)`
`mEq=mEq`
`Vxx0.1xx3-=40 mL xx0.25xx8`
`V=266.67 mL`
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